What is area 4sin(x),4cos(2x),-pi/2 , pi/6 ?

The answer to area 4sin(x),4cos(2x),-pi/2 , pi/6 is 3sqrt(3)

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area 4sin(x),4cos(2x),-pi/2 , pi/6

area

4 sin (x), 4 cos (2 x), - \frac{π}{2}, \frac{π}{6}

33

Decimal Notation

5.19615 \dots

Solution steps

Apply the area formula:

\int_{- \frac{π}{2}}^{\frac{π}{6}} ∣ 4 sin (x) - 4 cos (2 x) ∣ d x

Solve

\int_{- \frac{π}{2}}^{\frac{π}{6}} ∣ 4 sin (x) - 4 cos (2 x) ∣ d x : 33

The area is:

= 33

\frac{d}{d x} ((x - 1) (x + 1)^{2})

x \to 0 lim (x^{l n (x)})

e^{8 x}

x \to 0 lim (\frac{cot ( 7 x )}{csc ( 7 x )})

d r = b (cos (θ) d r + r sin (θ) d θ)

What is area 4sin(x),4cos(2x),-pi/2 , pi/6 ?
The answer to area 4sin(x),4cos(2x),-pi/2 , pi/6 is 3sqrt(3)