What is the solution for y^'+(1-2x)/(x^2)y=1 ?

The solution for y^'+(1-2x)/(x^2)y=1 is y=x^2+(c_{1}x^2}{e^{\frac{-1+2x+c_{1}x)/x}}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'+(1-2x)/(x^2)y=1

y^{^{'}} + \frac{1 - 2 x}{x ^{2}} y = 1

y = x^{2} + \frac{c _{1} x ^{2}}{e ^{\frac{- 1 + 2 x + c _{1} x}{x}}}

Solution steps

y^{'} (x) + \frac{1 - 2 x}{x ^{2}} y = 1

Solve linear ODE:

y = x^{2} + \frac{c _{1} x ^{2}}{e ^{\frac{- 1 + 2 x + c _{1} x}{x}}}

y = x^{2} + \frac{c _{1} x ^{2}}{e ^{\frac{- 1 + 2 x + c _{1} x}{x}}}

\frac{\partial}{\partial y} (2 x y^{4} - 1)

(5 x^{2} + 11 x)^{\frac{4}{3}}

\int e^{- x (y + 1)} d x

\int_{0}^{50} 9.8 (500 - 10 y) d y

\frac{\partial}{\partial t} (2 t)

What is the solution for y^'+(1-2x)/(x^2)y=1 ?
The solution for y^'+(1-2x)/(x^2)y=1 is y=x^2+(c_{1}x^2}{e^{\frac{-1+2x+c_{1}x)/x}}