What is laplacetransform t^2-2t+2 ?

The answer to laplacetransform t^2-2t+2 is 2/(s^3)-2/(s^2)+2/s

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laplacetransform t^2-2t+2

laplace transform

t^{2} - 2 t + 2

\frac{2}{s ^{3}} - \frac{2}{s ^{2}} + \frac{2}{s}

Solution steps

L {t^{2} - 2 t + 2}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= L {t^{2}} - 2 L {t} + L {2}

L {t^{2}} : \frac{2}{s ^{3}}

L {t} : \frac{1}{s ^{2}}

L {2} : \frac{2}{s}

= \frac{2}{s ^{3}} - 2 \cdot \frac{1}{s ^{2}} + \frac{2}{s}

Refine

\frac{2}{s ^{3}} - 2 \frac{1}{s ^{2}} + \frac{2}{s} : \frac{2}{s ^{3}} - \frac{2}{s ^{2}} + \frac{2}{s}

= \frac{2}{s ^{3}} - \frac{2}{s ^{2}} + \frac{2}{s}

t^{22} ln ∣ t ∣

\frac{d}{d x} (e^{2 x} + x e^{2 x})

3 - x, 0

(2 x)^{^{'}}

\frac{d}{d x} (x^{2} - 25)

What is laplacetransform t^2-2t+2 ?
The answer to laplacetransform t^2-2t+2 is 2/(s^3)-2/(s^2)+2/s