What is the derivative of 8tan(2x) ?

The derivative of 8tan(2x) is 16sec^2(2x)

What is the first derivative of 8tan(2x) ?

The first derivative of 8tan(2x) is 16sec^2(2x)

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derivative of

8 tan (2 x)

16 sec^{2} (2 x)

Solution steps

\frac{d}{d x} (8 tan (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (tan (2 x))

Apply the chain rule:

sec^{2} (2 x) \frac{d}{d x} (2 x)

= sec^{2} (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= 8 sec^{2} (2 x) \cdot 2

Simplify

= 16 sec^{2} (2 x)

\frac{d}{d x} (x^{2} - 64)

x \to 28 lim (\frac{x ^{2}}{4} - \frac{7}{x})

2 \frac{d y}{d x} - 4 x y = 8 x

x \to 2 lim ((x + 5) (x - 3))

What is the derivative of 8tan(2x) ?
The derivative of 8tan(2x) is 16sec^2(2x)
What is the first derivative of 8tan(2x) ?
The first derivative of 8tan(2x) is 16sec^2(2x)