What is the derivative of 2x^3-2x ?

The derivative of 2x^3-2x is 6x^2-2

What is the first derivative of 2x^3-2x ?

The first derivative of 2x^3-2x is 6x^2-2

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\frac{d}{d x} (2 x^{3} - 2 x)

6 x^{2} - 2

Solution steps

\frac{d}{d x} (2 x^{3} - 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) - \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (2 x) = 2

= 6 x^{2} - 2

\int x sin (s) d x

y = (7) (6^{x - 8})

x^{2} \frac{d y}{d x} + 4 x y - e^{x} = 0

(2 y - 8 x^{2}) d x + x d y = 0

\frac{d}{d x} (e^{x \cdot s i n (x)})

What is the derivative of 2x^3-2x ?
The derivative of 2x^3-2x is 6x^2-2
What is the first derivative of 2x^3-2x ?
The first derivative of 2x^3-2x is 6x^2-2