What is the derivative of (3x-1^3) ?

The derivative of (3x-1^3) is 9(3x-1)^2

What is the first derivative of (3x-1^3) ?

The first derivative of (3x-1^3) is 9(3x-1)^2

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\frac{d}{d x} ((3 x - 1)^{3})

9 (3 x - 1)^{2}

Solution steps

\frac{d}{d x} ((3 x - 1)^{3})

Apply the chain rule:

3 (3 x - 1)^{2} \frac{d}{d x} (3 x - 1)

= 3 (3 x - 1)^{2} \frac{d}{d x} (3 x - 1)

\frac{d}{d x} (3 x - 1) = 3

= 3 (3 x - 1)^{2} \cdot 3

Simplify

= 9 (3 x - 1)^{2}

\int \frac{ln ( x + 4 )}{x ^{2}} d x

\frac{d}{d x} (9 + 4 x)

\frac{\partial}{\partial x} (2 cos (x + 2 y))

x^{2} sin^{4} (x) + x cos^{- 2} (x)

\int \frac{x ^{2} - x}{x + 1} d x

What is the derivative of (3x-1^3) ?
The derivative of (3x-1^3) is 9(3x-1)^2
What is the first derivative of (3x-1^3) ?
The first derivative of (3x-1^3) is 9(3x-1)^2