What is the sum from n=1 to infinity of (n+1)^2 ?

The sum from n=1 to infinity of (n+1)^2 is diverges

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sum from n=1 to infinity of (n+1)^2

n = 1 \sum \infty (n + 1)^{2}

diverges

Solution steps

n = 1 \sum \infty (n + 1)^{2}

Apply Series Divergence Test:

diverges

= diverges

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What is the sum from n=1 to infinity of (n+1)^2 ?
The sum from n=1 to infinity of (n+1)^2 is diverges