What is the derivative of 2^{7x} ?

The derivative of 2^{7x} is 7ln(2)*128^x

What is the first derivative of 2^{7x} ?

The first derivative of 2^{7x} is 7ln(2)*128^x

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\frac{d}{d x} (2^{7 x})

7 ln (2) \cdot 12 8^{x}

Solution steps

\frac{d}{d x} (2^{7 x})

Simplify

2^{7 x} : 12 8^{x}

= \frac{d}{d x} (12 8^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= 12 8^{x} ln (128)

Simplify

ln (128) : 7 ln (2)

= 7 ln (2) \cdot 12 8^{x}

n = 0 \sum \infty 3 (x - 2)^{n}

x^{2} - 14 x + 48

\frac{d}{d x} (\frac{e ^{5 x^{2} - 2 x}}{cot ( 7 ^{x} )})

\frac{d}{d x} (8 cos^{3} (x))

arctan (8 x^{2} - 1)

What is the derivative of 2^{7x} ?
The derivative of 2^{7x} is 7ln(2)*128^x
What is the first derivative of 2^{7x} ?
The first derivative of 2^{7x} is 7ln(2)*128^x