What is the integral from 1/2 to 1 of x^{-3}-8 ?

The integral from 1/2 to 1 of x^{-3}-8 is -5/2

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integral from 1/2 to 1 of x^{-3}-8

\int_{\frac{1}{2}}^{1} x^{- 3} - 8 d x

- \frac{5}{2}

Decimal Notation

- 2.5

Solution steps

\int_{\frac{1}{2}}^{1} x^{- 3} - 8 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{\frac{1}{2}}^{1} x^{- 3} d x - \int_{\frac{1}{2}}^{1} 8 d x

\int_{\frac{1}{2}}^{1} x^{- 3} d x = \frac{3}{2}

\int_{\frac{1}{2}}^{1} 8 d x = 4

= \frac{3}{2} - 4

Simplify

\frac{3}{2} - 4 : - \frac{5}{2}

= - \frac{5}{2}

n = 1 \sum \infty x^{n} 8^{n}

\int \frac{3 x - 2}{x} d x

\frac{1}{( s ) ( s + 2 ) ( s + 3 )}

y^{^{'}} = \frac{e ^{x - y}}{1 + e ^{x}}, y (1) = 0

What is the integral from 1/2 to 1 of x^{-3}-8 ?
The integral from 1/2 to 1 of x^{-3}-8 is -5/2