What is the derivative of (ln(x))/(5x^2) ?

The derivative of (ln(x))/(5x^2) is (1-2ln(x))/(5x^3)

What is the first derivative of (ln(x))/(5x^2) ?

The first derivative of (ln(x))/(5x^2) is (1-2ln(x))/(5x^3)

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derivative of

\frac{ln ( x )}{5 x ^{2}}

\frac{1 - 2 ln ( x )}{5 x ^{3}}

Solution steps

\frac{d}{d x} (\frac{ln ( x )}{5 x ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{5} \frac{d}{d x} (\frac{ln ( x )}{x ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{1}{5} \cdot \frac{\frac{d}{d x} ( ln ( x ) ) x ^{2} - \frac{d}{d x} ( x ^{2} ) ln ( x )}{( x ^{2} ) ^{2}}

\frac{d}{d x} (ln (x)) = \frac{1}{x}

\frac{d}{d x} (x^{2}) = 2 x

= \frac{1}{5} \cdot \frac{\frac{1}{x} x ^{2} - 2 x ln ( x )}{( x ^{2} ) ^{2}}

Simplify

\frac{1}{5} \cdot \frac{\frac{1}{x} x ^{2} - 2 x ln ( x )}{( x ^{2} ) ^{2}} : \frac{1 - 2 ln ( x )}{5 x ^{3}}

= \frac{1 - 2 ln ( x )}{5 x ^{3}}

\frac{\partial}{\partial x} (e^{2 x + 7 y})

y^{^{''}} + 6 y^{^{'}} + 9 y = 6 t^{2} e^{- 3 t}

\frac{\partial}{\partial x} (x e^{x^{2} - y})

x \to 0 lim (\frac{9 e ^{x} - 9}{x})

f (x) = 4 sec (4 x)

What is the derivative of (ln(x))/(5x^2) ?
The derivative of (ln(x))/(5x^2) is (1-2ln(x))/(5x^3)
What is the first derivative of (ln(x))/(5x^2) ?
The first derivative of (ln(x))/(5x^2) is (1-2ln(x))/(5x^3)