What is the derivative of 3sin(2x+e^{-x}) ?

The derivative of 3sin(2x+e^{-x}) is 6cos(2x)-e^{-x}

What is the first derivative of 3sin(2x+e^{-x}) ?

The first derivative of 3sin(2x+e^{-x}) is 6cos(2x)-e^{-x}

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\frac{d}{d x} (3 sin (2 x) + e^{- x})

6 cos (2 x) - e^{- x}

Solution steps

\frac{d}{d x} (3 sin (2 x) + e^{- x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 sin (2 x)) + \frac{d}{d x} (e^{- x})

\frac{d}{d x} (3 sin (2 x)) = 6 cos (2 x)

\frac{d}{d x} (e^{- x}) = - e^{- x}

= 6 cos (2 x) - e^{- x}

\frac{( s ^{4} + 4 )}{s ^{4} - 4}

\int 7^{2 x + 3} d x

\frac{\partial}{\partial x} (- 6 y)

\frac{d}{d x} (\frac{5 - 2 x}{2 x + 1})

x \to 0 + lim (x^{- 5} ln (x))

What is the derivative of 3sin(2x+e^{-x}) ?
The derivative of 3sin(2x+e^{-x}) is 6cos(2x)-e^{-x}
What is the first derivative of 3sin(2x+e^{-x}) ?
The first derivative of 3sin(2x+e^{-x}) is 6cos(2x)-e^{-x}