What is the derivative of (96/x) ?

The derivative of (96/x) is -(96)/(x^2)

What is the first derivative of (96/x) ?

The first derivative of (96/x) is -(96)/(x^2)

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\frac{d}{d x} (\frac{96}{x})

- \frac{96}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{96}{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 96 \frac{d}{d x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 96 \frac{d}{d x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 96 (- 1 \cdot x^{- 1 - 1})

Simplify

96 (- 1 \cdot x^{- 1 - 1}) : - \frac{96}{x ^{2}}

= - \frac{96}{x ^{2}}

11 x - 4 y x^{2} + 1 y^{^{'}} = 0

f (x) = 11 x

\frac{d}{d x} (\frac{x + 3}{x - 3})

x^{2} \cdot ln (x)

\int \frac{3 x ^{2}}{x ^{2} - 4} d x

What is the derivative of (96/x) ?
The derivative of (96/x) is -(96)/(x^2)
What is the first derivative of (96/x) ?
The first derivative of (96/x) is -(96)/(x^2)