What is the derivative of (x^2-9)^2 ?

The derivative of (x^2-9)^2 is 4x(x^2-9)

What is the first derivative of (x^2-9)^2 ?

The first derivative of (x^2-9)^2 is 4x(x^2-9)

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derivative of

(x^{2} - 9)^{2}

4 x (x^{2} - 9)

Solution steps

\frac{d}{d x} ((x^{2} - 9)^{2})

Apply the chain rule:

2 (x^{2} - 9) \frac{d}{d x} (x^{2} - 9)

= 2 (x^{2} - 9) \frac{d}{d x} (x^{2} - 9)

\frac{d}{d x} (x^{2} - 9) = 2 x

= 2 (x^{2} - 9) \cdot 2 x

Simplify

= 4 x (x^{2} - 9)

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\int \frac{x ^{3} - 6 x ^{2} + 11 x - 6}{4 x ^{3} - 28 x ^{2} + 56 x - 32} d x

\int_{- \infty}^{0} e^{5 x} d x

\frac{\partial}{\partial x} (5 x ln (x^{2} + y))

What is the derivative of (x^2-9)^2 ?
The derivative of (x^2-9)^2 is 4x(x^2-9)
What is the first derivative of (x^2-9)^2 ?
The first derivative of (x^2-9)^2 is 4x(x^2-9)