What is the derivative of (f(x))/(g(x)+1) ?

The derivative of (f(x))/(g(x)+1) is x/(xg+1)

What is the first derivative of (f(x))/(g(x)+1) ?

The first derivative of (f(x))/(g(x)+1) is x/(xg+1)

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derivative of

\frac{f ( x )}{g ( x ) + 1}

\frac{x}{xg + 1}

Solution steps

\frac{d}{df} (\frac{f x}{gx + 1})

Treat

x, g

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{x}{gx + 1} \frac{df}{df}

Apply the common derivative:

\frac{df}{df} = 1

= \frac{x}{gx + 1} \cdot 1

Simplify

= \frac{x}{xg + 1}

\frac{x ^{2}}{3 + 8 x}

\int 3 t + 1 d t

\frac{d}{d x} (x^{3} - 3 x^{2} + 5 x - 2)

\frac{d}{d x} (a e^{x} + \frac{b}{x} + \frac{c}{x ^{2}})

f (x) = 7 x^{2} - x^{3}, at x = 1

What is the derivative of (f(x))/(g(x)+1) ?
The derivative of (f(x))/(g(x)+1) is x/(xg+1)
What is the first derivative of (f(x))/(g(x)+1) ?
The first derivative of (f(x))/(g(x)+1) is x/(xg+1)