What is the slope ofintercept (-10,3),(-8,-8) ?

The slope ofintercept (-10,3),(-8,-8) is y=-11/2 x-52

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slope ofintercept (-10,3),(-8,-8)

slope intercept

(- 10, 3), (- 8, - 8)

y = - \frac{11}{2} x - 52

Solution steps

Compute the slope

(- 10, 3), (- 8, - 8) : m = - \frac{11}{2}

Compute the

y

intercept:

b = - 52

Construct the line equation

y = mx + b

where

m = - \frac{11}{2}

and

b = - 52

y = - \frac{11}{2} x - 52

n = 0 \sum \infty (\frac{1}{5})^{n + 1}

\int (e^{x} + 2 x)^{2} d x

\int \frac{x ^{3}}{1 - x ^{4}} d x

f (x) = 5 - 3 x

\int_{- 1}^{1} (x^{2} - x) d x

What is the slope ofintercept (-10,3),(-8,-8) ?
The slope ofintercept (-10,3),(-8,-8) is y=-11/2 x-52