What is the derivative of 1-sin(3x) ?

The derivative of 1-sin(3x) is -3cos(3x)

What is the first derivative of 1-sin(3x) ?

The first derivative of 1-sin(3x) is -3cos(3x)

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\frac{d}{d x} (1 - sin (3 x))

- 3 cos (3 x)

Solution steps

\frac{d}{d x} (1 - sin (3 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} (sin (3 x))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (sin (3 x)) = cos (3 x) \cdot 3

= 0 - cos (3 x) \cdot 3

Simplify

= - 3 cos (3 x)

\frac{e ^{- 5 s}}{s ^{2}}

x \to 3 + lim (\frac{( x ^{2} )}{x - 3})

\int_{0}^{1} 2 π (2 - y) (5 y^{2}) d y

\frac{\partial}{\partial y} (2 y e^{- x})

\frac{d}{d x} (\frac{3 x}{x ^{2} + 3} + 98.6)

What is the derivative of 1-sin(3x) ?
The derivative of 1-sin(3x) is -3cos(3x)
What is the first derivative of 1-sin(3x) ?
The first derivative of 1-sin(3x) is -3cos(3x)