What is the solution for (d^2y)/(dx^2)+9y=10cos(2x) ?

The solution for (d^2y)/(dx^2)+9y=10cos(2x) is y=c_{1}cos(3x)+c_{2}sin(3x)+2cos(2x)

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(d^2y)/(dx^2)+9y=10cos(2x)

\frac{d ^{2} y}{d x ^{2}} + 9 y = 10 cos (2 x)

y = c_{1} cos (3 x) + c_{2} sin (3 x) + 2 cos (2 x)

Solution steps

\frac{d ^{2} y}{d x ^{2}} + 9 y = 10 cos (2 x)

Solve linear ODE:

y = c_{1} cos (3 x) + c_{2} sin (3 x) + 2 cos (2 x)

y = c_{1} cos (3 x) + c_{2} sin (3 x) + 2 cos (2 x)

\frac{x ^{3} + 8}{x}

x \to 0 + lim (lo g_{4} (2))

3 y^{^{''}} - 6 y^{^{'}} + 6 y = e^{x} sec (x)

\int 2 arctan (x) d x

What is the solution for (d^2y)/(dx^2)+9y=10cos(2x) ?
The solution for (d^2y)/(dx^2)+9y=10cos(2x) is y=c_{1}cos(3x)+c_{2}sin(3x)+2cos(2x)