What is the solution for (x/(2y^4))dx+((3y^2-x^2)/(y^5))dy=0 ?

The solution for (x/(2y^4))dx+((3y^2-x^2)/(y^5))dy=0 is

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(x/(2y^4))dx+((3y^2-x^2)/(y^5))dy=0

(\frac{x}{2 y ^{4}}) d x + (\frac{3 y ^{2} - x ^{2}}{y ^{5}}) d y = 0

y = \frac{- 3 + 2 c _{1} x ^{2} + 9}{2 c _{1}}, y = - \frac{- 3 + 2 c _{1} x ^{2} + 9}{2 c _{1}}, y = - \frac{2 c _{1} x ^{2} + 9 + 3}{2 c _{1}}, y = - - \frac{2 c _{1} x ^{2} + 9 + 3}{2 c _{1}}

Solution steps

(\frac{x}{2 y ^{4}}) d x + (\frac{3 y ^{2} - x ^{2}}{y ^{5}}) d y = 0

Solve exact ODE:

y = \frac{- 3 + 2 c _{1} x ^{2} + 9}{2 c _{1}}, y = - \frac{- 3 + 2 c _{1} x ^{2} + 9}{2 c _{1}}, y = - \frac{2 c _{1} x ^{2} + 9 + 3}{2 c _{1}}, y = - - \frac{2 c _{1} x ^{2} + 9 + 3}{2 c _{1}}

y = \frac{- 3 + 2 c _{1} x ^{2} + 9}{2 c _{1}}, y = - \frac{- 3 + 2 c _{1} x ^{2} + 9}{2 c _{1}}, y = - \frac{2 c _{1} x ^{2} + 9 + 3}{2 c _{1}}, y = - - \frac{2 c _{1} x ^{2} + 9 + 3}{2 c _{1}}

\frac{d}{d x} (5 x^{2} + 2 x)

\int x ln (3 x) d x

\int \frac{5 x ^{2}}{( 144 + x ^{2} ) ^{2}} d x

\int \frac{x ^{2}}{e ^{(x^{3})}} d x

x \to 0 + lim (\frac{4 x}{sin ( x )})

What is the solution for (x/(2y^4))dx+((3y^2-x^2)/(y^5))dy=0 ?
The solution for (x/(2y^4))dx+((3y^2-x^2)/(y^5))dy=0 is