What is the solution for 2ycos(x)dx+3sin(x)dy=0 ?

The solution for 2ycos(x)dx+3sin(x)dy=0 is y=(c_{1})/(sin^{2/3)(x)}

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2ycos(x)dx+3sin(x)dy=0

2 y cos (x) d x + 3 sin (x) d y = 0

y = \frac{c _{1}}{sin ^{\frac{2}{3}} ( x )}

Solution steps

2 y cos (x) d x + 3 sin (x) d y = 0

Solve separable ODE:

y = \frac{c _{1}}{sin ^{\frac{2}{3}} ( x )}

y = \frac{c _{1}}{sin ^{\frac{2}{3}} ( x )}

e^{x} y \frac{d y}{d x} = e^{- y} + e^{- 2 x - y}

y^{^{'}} + 5 x^{4} y = x^{4}

\int \frac{y}{x ^{2} + y ^{2}} d y

\frac{\partial}{\partial x} (x y^{2} - y x^{3})

\frac{d}{d x} (1 + 40 x^{3} - 3 x^{5})

What is the solution for 2ycos(x)dx+3sin(x)dy=0 ?
The solution for 2ycos(x)dx+3sin(x)dy=0 is y=(c_{1})/(sin^{2/3)(x)}