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Popular >

f(x)=ln(x^2+x+1)

Solution

f (x) = ln (x^{2} + x + 1)

Solution

Domain : - \infty < x < \infty

Range : f (x) \geq ln (\frac{3}{4})

X Intercepts : (0, 0), (- 1, 0), Y Intercepts : (0, 0)

Asymptotes : None

Extreme Points : Minimum (- \frac{1}{2}, ln (\frac{3}{4}))

+1

Interval Notation

Domain : (- \infty, \infty)

Range : [ln (\frac{3}{4}), \infty)

Solution steps

Domain of

ln (x^{2} + x + 1) : - \infty < x < \infty

Range of

ln (x^{2} + x + 1) : f (x) \geq ln (\frac{3}{4})

Axis interception points of

ln (x^{2} + x + 1) :

X Intercepts

: (0, 0), (- 1, 0),

Y Intercepts

: (0, 0)

Asymptotes of

ln (x^{2} + x + 1) :

None

Extreme Points of

ln (x^{2} + x + 1) :

Minimum

(- \frac{1}{2}, ln (\frac{3}{4}))

Popular Examples

y^{^{''''}} - y = 0

integral of x^{-1}

\int x^{- 1} d x

integral from 0 to 2 of e^{-t}

\int_{0}^{2} e^{- t} d t

limit as x approaches infinity of 8+5/x

x \to \infty lim (8 + \frac{5}{x})

derivative of-5/((x-2^2))

\frac{d}{d x} (- \frac{5}{( x - 2 ) ^{2}})

Frequently Asked Questions (FAQ)

What is the f(x)=ln(x^2+x+1) ?
The f(x)=ln(x^2+x+1) is