What is the solution for (dy)/(dx)=((y-1))/(x+3) ?

The solution for (dy)/(dx)=((y-1))/(x+3) is y=e^{c_{1}}x+3e^{c_{1}}+1

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(dy)/(dx)=((y-1))/(x+3)

\frac{d y}{d x} = \frac{( y - 1 )}{x + 3}

y = e^{c_{1}} x + 3 e^{c_{1}} + 1

Solution steps

\frac{d y}{d x} = \frac{( y - 1 )}{x + 3}

Solve separable ODE:

y = e^{c_{1}} x + 3 e^{c_{1}} + 1

y = e^{c_{1}} x + 3 e^{c_{1}} + 1

y^{^{'}} + \frac{y}{x} = 7 x^{3} y^{2}

3^{x}

\frac{d}{d x} (e^{3 x} sin (x))

\int x^{2} (1 - x^{3})^{4} d x

\frac{s ^{2} - 2 s + 3}{( s - 2 ) ^{3}}

What is the solution for (dy)/(dx)=((y-1))/(x+3) ?
The solution for (dy)/(dx)=((y-1))/(x+3) is y=e^{c_{1}}x+3e^{c_{1}}+1