What is the derivative of 8^{4x} ?

The derivative of 8^{4x} is 3ln(2)*2^{12x+2}

What is the first derivative of 8^{4x} ?

The first derivative of 8^{4x} is 3ln(2)*2^{12x+2}

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\frac{d}{d x} (8^{4 x})

3 ln (2) \cdot 2^{12 x + 2}

Solution steps

\frac{d}{d x} (8^{4 x})

Simplify

8^{4 x} : 409 6^{x}

= \frac{d}{d x} (409 6^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= 409 6^{x} ln (4096)

Simplify

409 6^{x} ln (4096) : 3 ln (2) \cdot 2^{12 x + 2}

= 3 ln (2) \cdot 2^{12 x + 2}

\frac{\partial}{\partial y} (x 1 + y^{9})

\frac{6 x}{3 - tan ( x )}

\int 8 sin^{4} (r) cos (r) d r

\int x^{2} sin (4 x^{3} + 7) d x

f (x) = 18 x - 3 x^{2}

What is the derivative of 8^{4x} ?
The derivative of 8^{4x} is 3ln(2)*2^{12x+2}
What is the first derivative of 8^{4x} ?
The first derivative of 8^{4x} is 3ln(2)*2^{12x+2}