What is the derivative of 1-1/(1+x) ?

The derivative of 1-1/(1+x) is 1/((x+1)^2)

What is the first derivative of 1-1/(1+x) ?

The first derivative of 1-1/(1+x) is 1/((x+1)^2)

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Popular >

\frac{d}{d x} (1 - \frac{1}{1 + x})

\frac{1}{( x + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (1 - \frac{1}{1 + x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} (\frac{1}{1 + x})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (\frac{1}{1 + x}) = - \frac{1}{( 1 + x ) ^{2}}

= 0 - (- \frac{1}{( 1 + x ) ^{2}})

Simplify

= \frac{1}{( x + 1 ) ^{2}}

\frac{\partial}{\partial x} (\frac{4 x - 4 z}{3 y + 4 z})

\int cos^{2} (\frac{1}{2}) x d x

\frac{3 s}{( s - 1 ) ( s ^{2} - 4 )}

\int \frac{( 6 x - 7 )}{3 x ^{2} - 7 x + 11} d x

(2, - 3), (- 1, 15)

What is the derivative of 1-1/(1+x) ?
The derivative of 1-1/(1+x) is 1/((x+1)^2)
What is the first derivative of 1-1/(1+x) ?
The first derivative of 1-1/(1+x) is 1/((x+1)^2)