What is (\partial)/(\partial x)(x^2y-x^3) ?

The answer to (\partial)/(\partial x)(x^2y-x^3) is 2yx-3x^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(x^2y-x^3)

\frac{\partial}{\partial x} (x^{2} y - x^{3})

2 y x - 3 x^{2}

Solution steps

\frac{\partial}{\partial x} (x^{2} y - x^{3})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2} y) - \frac{\partial}{\partial x} (x^{3})

\frac{\partial}{\partial x} (x^{2} y) = 2 y x

\frac{\partial}{\partial x} (x^{3}) = 3 x^{2}

= 2 y x - 3 x^{2}

\frac{\partial}{\partial x} (6 x y^{2} - 2 x^{3} - 3 y^{4})

\frac{d ^{2} y}{d x ^{2}} = 3

\frac{\partial}{\partial x} (2 x + 4 y)

\frac{d}{d x} (2 x \cdot e^{x})

\int \frac{1}{4 sin ( x )} d x

What is (\partial)/(\partial x)(x^2y-x^3) ?
The answer to (\partial)/(\partial x)(x^2y-x^3) is 2yx-3x^2