What is the derivative of f(x)=18x-3x^2 ?

The derivative of f(x)=18x-3x^2 is 18-6x

What is the first derivative of f(x)=18x-3x^2 ?

The first derivative of f(x)=18x-3x^2 is 18-6x

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derivative of

f (x) = 18 x - 3 x^{2}

18 - 6 x

Solution steps

\frac{d}{d x} (18 x - 3 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (18 x) - \frac{d}{d x} (3 x^{2})

\frac{d}{d x} (18 x) = 18

\frac{d}{d x} (3 x^{2}) = 6 x

= 18 - 6 x

\int \frac{1}{z ^{2} 9 - z ^{2}} d z

\frac{4 s + 2}{s ^{2} + 8 s + 16}

\int \frac{1}{x ^{5} + 2 x ^{3} + x} d x

\int_{0}^{10} 400 - 20 x d x

f (t) = 5 t

What is the derivative of f(x)=18x-3x^2 ?
The derivative of f(x)=18x-3x^2 is 18-6x
What is the first derivative of f(x)=18x-3x^2 ?
The first derivative of f(x)=18x-3x^2 is 18-6x