What is the derivative of g(x)=x^2+sin(x) ?

The derivative of g(x)=x^2+sin(x) is 2x+cos(x)

What is the first derivative of g(x)=x^2+sin(x) ?

The first derivative of g(x)=x^2+sin(x) is 2x+cos(x)

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derivative of

g (x) = x^{2} + sin (x)

2 x + cos (x)

Solution steps

\frac{d}{d x} (x^{2} + sin (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (sin (x))

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (sin (x)) = cos (x)

= 2 x + cos (x)

f (x) = (x - 3 x^{4}) tan (x)

\int 200 - 20 x - 3 x^{2} d x

\frac{d}{d x} (ln (x) \cdot e^{2 x})

\frac{\partial}{\partial x} (x^{2} y + 3 y^{2} - y)

(\frac{e ^{4 x^{2}}}{x ^{2}})^{^{'}}

What is the derivative of g(x)=x^2+sin(x) ?
The derivative of g(x)=x^2+sin(x) is 2x+cos(x)
What is the first derivative of g(x)=x^2+sin(x) ?
The first derivative of g(x)=x^2+sin(x) is 2x+cos(x)