What is the derivative of 2sin(pix-y) ?

The derivative of 2sin(pix-y) is 2cos(pix-y)(pi-(dy)/(dx))

What is the first derivative of 2sin(pix-y) ?

The first derivative of 2sin(pix-y) is 2cos(pix-y)(pi-(dy)/(dx))

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\frac{d}{d x} (2 sin (π x - y))

2 cos (π x - y) (π - \frac{d y}{d x})

Solution steps

\frac{d}{d x} (2 sin (π x - y))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (sin (π x - y))

Apply the chain rule:

cos (π x - y) \frac{d}{d x} (π x - y)

= cos (π x - y) \frac{d}{d x} (π x - y)

\frac{d}{d x} (π x - y) = π - \frac{d y}{d x}

= 2 cos (π x - y) (π - \frac{d y}{d x})

\frac{2}{x}, - 3 x + 7, - 2 x + 4

\frac{d}{d x} (ln (ln (10 x)))

y^{^{'}} + (\frac{4}{x}) y = x^{4}

x \to - 2 lim (tan (\frac{π x}{4}))

\frac{d}{d x} (\frac{ln ( x )}{ln ( x ) + 2})

What is the derivative of 2sin(pix-y) ?
The derivative of 2sin(pix-y) is 2cos(pix-y)(pi-(dy)/(dx))
What is the first derivative of 2sin(pix-y) ?
The first derivative of 2sin(pix-y) is 2cos(pix-y)(pi-(dy)/(dx))