What is the tangent of y= 6/(sqrt(x)),(36, 6/6) ?

The tangent of y= 6/(sqrt(x)),(36, 6/6) is y=-1/72 x+3/2

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tangent of y= 6/(sqrt(x)),(36, 6/6)

tangent of

y = \frac{6}{x}, (36, \frac{6}{6})

y = - \frac{1}{72} x + \frac{3}{2}

Solution steps

Find the slope of

y = \frac{6}{x} : \frac{d y}{d x} = - \frac{3}{x ^{\frac{3}{2}}}

Compute the slope of

y = \frac{6}{x}

(36, \frac{6}{6}) : m = - \frac{1}{72}

Find the line with slope m=

- \frac{1}{72}

and passing through

(36, \frac{6}{6}) : y = - \frac{1}{72} x + \frac{3}{2}

y = - \frac{1}{72} x + \frac{3}{2}

\frac{d y}{d x} = - 2 y + e^{x}

\int_{0}^{\frac{π}{6}} 4 cos^{5} (3 x) d x

\int \frac{2}{x} + 3 sin (x) - 4 e^{x} d x

\frac{\partial}{\partial x} (6 z e^{x yz})

y^{^{'}} = 20 - 4 y

What is the tangent of y= 6/(sqrt(x)),(36, 6/6) ?
The tangent of y= 6/(sqrt(x)),(36, 6/6) is y=-1/72 x+3/2