What is the derivative of (2x^2+7^5) ?

The derivative of (2x^2+7^5) is 20x(2x^2+7)^4

What is the first derivative of (2x^2+7^5) ?

The first derivative of (2x^2+7^5) is 20x(2x^2+7)^4

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\frac{d}{d x} ((2 x^{2} + 7)^{5})

20 x (2 x^{2} + 7)^{4}

Solution steps

\frac{d}{d x} ((2 x^{2} + 7)^{5})

Apply the chain rule:

5 (2 x^{2} + 7)^{4} \frac{d}{d x} (2 x^{2} + 7)

= 5 (2 x^{2} + 7)^{4} \frac{d}{d x} (2 x^{2} + 7)

\frac{d}{d x} (2 x^{2} + 7) = 4 x

= 5 (2 x^{2} + 7)^{4} \cdot 4 x

Simplify

= 20 x (2 x^{2} + 7)^{4}

x \to 0 lim ((e^{x} + x)^{\frac{5}{x}})

\int sin^{2} (2 π x) d x

x \to - 2 lim (\frac{x - 2}{∣ x - 2 ∣})

x \to 0 lim (\frac{cos ( π x )}{x})

t e^{- 3 t}

What is the derivative of (2x^2+7^5) ?
The derivative of (2x^2+7^5) is 20x(2x^2+7)^4
What is the first derivative of (2x^2+7^5) ?
The first derivative of (2x^2+7^5) is 20x(2x^2+7)^4