What is the derivative of y=(18)/(x^4) ?

The derivative of y=(18)/(x^4) is -(72)/(x^5)

What is the first derivative of y=(18)/(x^4) ?

The first derivative of y=(18)/(x^4) is -(72)/(x^5)

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derivative of

y = \frac{18}{x ^{4}}

- \frac{72}{x ^{5}}

Solution steps

\frac{d}{d x} (\frac{18}{x ^{4}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 18 \frac{d}{d x} (\frac{1}{x ^{4}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 18 \frac{d}{d x} (x^{- 4})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 18 (- 4 x^{- 4 - 1})

Simplify

18 (- 4 x^{- 4 - 1}) : - \frac{72}{x ^{5}}

= - \frac{72}{x ^{5}}

\frac{d}{d x} (cos (e^{x^{4} c o s (x)}))

x \to 0 lim (\frac{2 ∣ x ∣}{3 x})

y = e^{9 - x}

\frac{\partial}{\partial x} (10 y + x)

\int 4 (x^{2} + 1) d x

What is the derivative of y=(18)/(x^4) ?
The derivative of y=(18)/(x^4) is -(72)/(x^5)
What is the first derivative of y=(18)/(x^4) ?
The first derivative of y=(18)/(x^4) is -(72)/(x^5)