What is the derivative of f(x)=(x^2-1)/2 ?

The derivative of f(x)=(x^2-1)/2 is x

What is the first derivative of f(x)=(x^2-1)/2 ?

The first derivative of f(x)=(x^2-1)/2 is x

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derivative of

f (x) = \frac{x ^{2} - 1}{2}

x

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 1}{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{d}{d x} (x^{2} - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{2} (\frac{d}{d x} (x^{2}) - \frac{d}{d x} (1))

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (1) = 0

= \frac{1}{2} (2 x - 0)

Simplify

\frac{1}{2} (2 x - 0) : x

= x

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What is the derivative of f(x)=(x^2-1)/2 ?
The derivative of f(x)=(x^2-1)/2 is x
What is the first derivative of f(x)=(x^2-1)/2 ?
The first derivative of f(x)=(x^2-1)/2 is x