What is (\partial)/(\partial x)(240x^2-140y^2) ?

The answer to (\partial)/(\partial x)(240x^2-140y^2) is 480x

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(\partial)/(\partial x)(240x^2-140y^2)

\frac{\partial}{\partial x} (240 x^{2} - 140 y^{2})

480 x

Solution steps

\frac{\partial}{\partial x} (240 x^{2} - 140 y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (240 x^{2}) - \frac{\partial}{\partial x} (140 y^{2})

\frac{\partial}{\partial x} (240 x^{2}) = 480 x

\frac{\partial}{\partial x} (140 y^{2}) = 0

= 480 x - 0

Simplify

= 480 x

t cos (5 t)

x \to - 9 lim (- 9)

\frac{d}{d v} (uv)

\int (x - \frac{3}{x})^{2} d x

\int \frac{3}{1 - 2 x} d x

What is (\partial)/(\partial x)(240x^2-140y^2) ?
The answer to (\partial)/(\partial x)(240x^2-140y^2) is 480x