What is the limit as x approaches 5 of-((x+1)/(x-5)) ?

The limit as x approaches 5 of-((x+1)/(x-5)) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 5 of-((x+1)/(x-5))

x \to 5 lim (- (\frac{x + 1}{x - 5}))

diverges

Solution steps

x \to 5 lim (- \frac{x + 1}{x - 5})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 5 + lim (- \frac{x + 1}{x - 5}) = - \infty

x \to 5 - lim (- \frac{x + 1}{x - 5}) = \infty

= diverges

\int \frac{x}{5} d x

\frac{d}{d x} (\frac{5}{3 x})

f (x) = \frac{( e ^{2 x} + 1 )}{e ^{x} - 2}

x^{4} - 3 x^{3} + 5

y = e^{\frac{8}{9} x}

What is the limit as x approaches 5 of-((x+1)/(x-5)) ?
The limit as x approaches 5 of-((x+1)/(x-5)) is diverges