What is the derivative of (3x-1(x+2)) ?

The derivative of (3x-1(x+2)) is 6x+5

What is the first derivative of (3x-1(x+2)) ?

The first derivative of (3x-1(x+2)) is 6x+5

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\frac{d}{d x} ((3 x - 1) (x + 2))

6 x + 5

Solution steps

\frac{d}{d x} ((3 x - 1) (x + 2))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 3 x - 1, g = x + 2

= \frac{d}{d x} (3 x - 1) (x + 2) + \frac{d}{d x} (x + 2) (3 x - 1)

\frac{d}{d x} (3 x - 1) = 3

\frac{d}{d x} (x + 2) = 1

= 3 (x + 2) + 1 \cdot (3 x - 1)

Simplify

3 (x + 2) + 1 \cdot (3 x - 1) : 6 x + 5

= 6 x + 5

x \to 0 + lim (2 - x)

y^{^{'}} = y - 8

\int_{0}^{1} 7 x^{4} e^{- x} d x

\int \frac{21}{21 + e ^{x}} d x

y^{^{'}} = \frac{3 x ^{2} + 2 x + 1}{y - 2}

What is the derivative of (3x-1(x+2)) ?
The derivative of (3x-1(x+2)) is 6x+5
What is the first derivative of (3x-1(x+2)) ?
The first derivative of (3x-1(x+2)) is 6x+5