What is the derivative of sin(x^3-3x) ?

The derivative of sin(x^3-3x) is cos(x^3-3x)(3x^2-3)

What is the first derivative of sin(x^3-3x) ?

The first derivative of sin(x^3-3x) is cos(x^3-3x)(3x^2-3)

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\frac{d}{d x} (sin (x^{3} - 3 x))

cos (x^{3} - 3 x) (3 x^{2} - 3)

Solution steps

\frac{d}{d x} (sin (x^{3} - 3 x))

Apply the chain rule:

cos (x^{3} - 3 x) \frac{d}{d x} (x^{3} - 3 x)

= cos (x^{3} - 3 x) \frac{d}{d x} (x^{3} - 3 x)

\frac{d}{d x} (x^{3} - 3 x) = 3 x^{2} - 3

= cos (x^{3} - 3 x) (3 x^{2} - 3)

x^{- 1} - \frac{1}{x}

f (x) = x e^{2 x}

\int \frac{x ^{5}}{x ^{6} - 6} d x

\int \frac{e ^{t}}{1 + e ^{2 t}} d t

x \to - 5 + lim (\frac{∣ x + 5 ∣}{x + 5})

What is the derivative of sin(x^3-3x) ?
The derivative of sin(x^3-3x) is cos(x^3-3x)(3x^2-3)
What is the first derivative of sin(x^3-3x) ?
The first derivative of sin(x^3-3x) is cos(x^3-3x)(3x^2-3)