What is the derivative of f(x)=arccos(3x) ?

The derivative of f(x)=arccos(3x) is -3/(sqrt(1-9x^2))

What is the first derivative of f(x)=arccos(3x) ?

The first derivative of f(x)=arccos(3x) is -3/(sqrt(1-9x^2))

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derivative of

f (x) = arccos (3 x)

- \frac{3}{1 - 9 x ^{2}}

Solution steps

\frac{d}{d x} (arccos (3 x))

Apply the chain rule:

- \frac{1}{1 - ( 3 x ) ^{2}} \frac{d}{d x} (3 x)

= - \frac{1}{1 - ( 3 x ) ^{2}} \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= - \frac{1}{1 - ( 3 x ) ^{2}} \cdot 3

Simplify

- \frac{1}{1 - ( 3 x ) ^{2}} \cdot 3 : - \frac{3}{1 - 9 x ^{2}}

= - \frac{3}{1 - 9 x ^{2}}

\frac{d}{d x} (arctan (x - 1 + x^{2}))

\frac{d y}{d x} = x^{2} (1 - y)

\frac{\partial}{\partial y} (2 x^{2} y - 5 y^{2})

\int \frac{cos ( x )}{( 1 + sin ( x ) ) ^{5}} d x

What is the derivative of f(x)=arccos(3x) ?
The derivative of f(x)=arccos(3x) is -3/(sqrt(1-9x^2))
What is the first derivative of f(x)=arccos(3x) ?
The first derivative of f(x)=arccos(3x) is -3/(sqrt(1-9x^2))