What is the limit as x approaches-1+of ln(x+1) ?

The limit as x approaches-1+of ln(x+1) is -infinity

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limit as x approaches-1+of ln(x+1)

x \to - 1 + lim (ln (x + 1))

- \infty

Solution steps

x \to - 1 + lim (ln (x + 1))

Apply the Limit Chain Rule:

- \infty

= - \infty

\frac{d}{d x} ((x - 4) (x + 1) (x + 5))

f (x) = \frac{x ^{3}}{3 - x ^{2}}

\int \frac{( 4 x - 5 ) ( 2 x - 7 )}{3} d x

\frac{\partial}{\partial x} (ln (x^{2} + 6 y^{2} + 8))

\frac{d y}{d x} = (y + 8)

What is the limit as x approaches-1+of ln(x+1) ?
The limit as x approaches-1+of ln(x+1) is -infinity