What is (\partial)/(\partial x)((t+1)/(t-1)) ?

The answer to (\partial)/(\partial x)((t+1)/(t-1)) is 0

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(\partial)/(\partial x)((t+1)/(t-1))

\frac{\partial}{\partial x} (\frac{t + 1}{t - 1})

0

Solution steps

\frac{\partial}{\partial x} (\frac{t + 1}{t - 1})

Treat

t

as a constant

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

\frac{d ^{4}}{d x ^{4}} (cos (x^{2}))

\int_{- 2}^{2} 2 x^{2} - 2 x d x

\int_{0}^{x} f (t) d t

f (x) = \frac{3}{1 + x ^{2}}

\frac{\partial}{\partial x} (- \frac{2 y}{( 2 x + 3 y ) ^{2}})

What is (\partial)/(\partial x)((t+1)/(t-1)) ?
The answer to (\partial)/(\partial x)((t+1)/(t-1)) is 0