What is the derivative of e^xy ?

The derivative of e^xy is e^xy+(dy)/(dx)e^x

What is the first derivative of e^xy ?

The first derivative of e^xy is e^xy+(dy)/(dx)e^x

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\frac{d}{d x} (e^{x} y)

e^{x} y + \frac{d y}{d x} e^{x}

Solution steps

\frac{d}{d x} (e^{x} y)

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = e^{x}, g = y

= \frac{d}{d x} (e^{x}) y + \frac{d y}{d x} e^{x}

\frac{d}{d x} (e^{x}) = e^{x}

= e^{x} y + \frac{d y}{d x} e^{x}

f (x) = sin (sin (x)), (π, 0)

\int \frac{9 x ( 6 x ^{2} + 5 ) ^{\frac{1}{2}}}{2} d x

\int \frac{1}{19 y} d y

\frac{4}{s ^{2} + 7 s + 12}

x \to 0 lim (e^{x} + 1)

What is the derivative of e^xy ?
The derivative of e^xy is e^xy+(dy)/(dx)e^x
What is the first derivative of e^xy ?
The first derivative of e^xy is e^xy+(dy)/(dx)e^x