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Popular >

y^'=ty

Solution

y^{^{'}} = t y

Solution

y = e^{\frac{t ^{2}}{2} + c_{1}}

Solution steps

y^{'} (t) = t y

Solve separable ODE:

y = e^{\frac{t ^{2}}{2} + c_{1}}

y = e^{\frac{t ^{2}}{2} + c_{1}}

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t \to 0 lim (\frac{2 e ^{t} - 2}{t})

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\int 2 + 2 cos (x) d x

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\int \frac{1}{3 - 4 x - x ^{2}} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=ty ?
The solution for y^'=ty is y=e^{(t^2)/2+c_{1}}