What is the solution for dy=(x-2ycot(2x))dx ?

The solution for dy=(x-2ycot(2x))dx is y=-(xcos(2x))/(2sin(2x))+1/4+(c_{1})/(sin(2x))

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dy=(x-2ycot(2x))dx

d y = (x - 2 y cot (2 x)) d x

y = - \frac{x cos ( 2 x )}{2 sin ( 2 x )} + \frac{1}{4} + \frac{c _{1}}{sin ( 2 x )}

Solution steps

d y = (x - 2 y cot (2 x)) d x

Solve linear ODE:

y = - \frac{x cos ( 2 x )}{2 sin ( 2 x )} + \frac{1}{4} + \frac{c _{1}}{sin ( 2 x )}

y = - \frac{x cos ( 2 x )}{2 sin ( 2 x )} + \frac{1}{4} + \frac{c _{1}}{sin ( 2 x )}

x (8 x + 5)^{4}

x^{3} e^{x} cos (x)

\int \frac{2 x + 4}{x ^{2} - 2 x - 3} d x

\int 3 x^{3} + 4 x^{2} - 2 x^{- 1} + 13 d x

\int - y^{3} d y

What is the solution for dy=(x-2ycot(2x))dx ?
The solution for dy=(x-2ycot(2x))dx is y=-(xcos(2x))/(2sin(2x))+1/4+(c_{1})/(sin(2x))