What is (\partial)/(\partial x)(-6y^3+10x^2-4xy) ?

The answer to (\partial)/(\partial x)(-6y^3+10x^2-4xy) is 20x-4y

Popular >

(\partial)/(\partial x)(-6y^3+10x^2-4xy)

\frac{\partial}{\partial x} (- 6 y^{3} + 10 x^{2} - 4 x y)

20 x - 4 y

Solution steps

\frac{\partial}{\partial x} (- 6 y^{3} + 10 x^{2} - 4 x y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{\partial}{\partial x} (6 y^{3}) + \frac{\partial}{\partial x} (10 x^{2}) - \frac{\partial}{\partial x} (4 x y)

\frac{\partial}{\partial x} (6 y^{3}) = 0

\frac{\partial}{\partial x} (10 x^{2}) = 20 x

\frac{\partial}{\partial x} (4 x y) = 4 y

= - 0 + 20 x - 4 y

Simplify

= 20 x - 4 y

y = 7 - 2 x^{2}, y = x^{2} + 4

\frac{\partial}{\partial x} (e^{\frac{- x}{x ^{2} + y ^{2}}})

- \frac{1}{t ^{3}}

f (x) = \frac{x}{3 x + 8}

x \to - 1 lim (\frac{x ^{2} - 1}{x - 3})

What is (\partial)/(\partial x)(-6y^3+10x^2-4xy) ?
The answer to (\partial)/(\partial x)(-6y^3+10x^2-4xy) is 20x-4y