What is area f(x)=-x^2+4x+2,g(x)=x+2 ?

The answer to area f(x)=-x^2+4x+2,g(x)=x+2 is 9/2

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area f(x)=-x^2+4x+2,g(x)=x+2

area

f (x) = - x^{2} + 4 x + 2, g (x) = x + 2

\frac{9}{2}

Decimal Notation

4.5

Solution steps

Apply the area formula:

\int_{0}^{3} - x^{2} + 4 x + 2 - (x + 2) d x

Solve

\int_{0}^{3} - x^{2} + 4 x + 2 - (x + 2) d x : \frac{9}{2}

The area is:

= \frac{9}{2}

10 x + 2

n = 0 \sum \infty c n x^{n}

\frac{\partial}{\partial x} (sin (y))

ln (1 - x)

\frac{d}{d t} (\frac{2}{3} t^{3})

What is area f(x)=-x^2+4x+2,g(x)=x+2 ?
The answer to area f(x)=-x^2+4x+2,g(x)=x+2 is 9/2