What is (\partial)/(\partial x)(x/(x^2+9y^2)) ?

The answer to (\partial)/(\partial x)(x/(x^2+9y^2)) is (-x^2+9y^2)/((x^2+9y^2)^2)

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(\partial)/(\partial x)(x/(x^2+9y^2))

\frac{\partial}{\partial x} (\frac{x}{x ^{2} + 9 y ^{2}})

\frac{- x ^{2} + 9 y ^{2}}{( x ^{2} + 9 y ^{2} ) ^{2}}

Solution steps

\frac{\partial}{\partial x} (\frac{x}{x ^{2} + 9 y ^{2}})

Treat

y

as a constant

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{\partial}{\partial x} ( x ) ( x ^{2} + 9 y ^{2} ) - \frac{\partial}{\partial x} ( x ^{2} + 9 y ^{2} ) x}{( x ^{2} + 9 y ^{2} ) ^{2}}

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (x^{2} + 9 y^{2}) = 2 x

= \frac{1 \cdot ( x ^{2} + 9 y ^{2} ) - 2 xx}{( x ^{2} + 9 y ^{2} ) ^{2}}

1 \cdot (x^{2} + 9 y^{2}) - 2 xx = - x^{2} + 9 y^{2}

= \frac{- x ^{2} + 9 y ^{2}}{( x ^{2} + 9 y ^{2} ) ^{2}}

\int (x + 1 + x^{2})^{6} d x

\int sec^{4} (5 x) tan (5 x) d x

x \to 2 lim (sin (\frac{p i x}{2}))

\frac{d}{d x} (5 x^{2} e^{- x})

(r^{6} - 9 r) e^{r}

What is (\partial)/(\partial x)(x/(x^2+9y^2)) ?
The answer to (\partial)/(\partial x)(x/(x^2+9y^2)) is (-x^2+9y^2)/((x^2+9y^2)^2)