What is the tangent of 2x^2+3x,\at x=-3 ?

The tangent of 2x^2+3x,\at x=-3 is y=-9x-18

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tangent of 2x^2+3x,\at x=-3

tangent of

2 x^{2} + 3 x, at x = - 3

y = - 9 x - 18

Solution steps

Find the tangent point:

(- 3, 9)

Find the slope of

y = 2 x^{2} + 3 x : \frac{d y}{d x} = 4 x + 3

Compute the slope of

y = 2 x^{2} + 3 x

x = - 3 : m = - 9

Find the line with slope m=

- 9

and passing through

(- 3, 9) : y = - 9 x - 18

y = - 9 x - 18

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What is the tangent of 2x^2+3x,\at x=-3 ?
The tangent of 2x^2+3x,\at x=-3 is y=-9x-18