What is the derivative of 3x^{-5} ?

The derivative of 3x^{-5} is -(15)/(x^6)

What is the first derivative of 3x^{-5} ?

The first derivative of 3x^{-5} is -(15)/(x^6)

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derivative of

3 x^{- 5}

- \frac{15}{x ^{6}}

Solution steps

\frac{d}{d x} (3 x^{- 5})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (x^{- 5})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 3 (- 5 x^{- 5 - 1})

Simplify

3 (- 5 x^{- 5 - 1}) : - \frac{15}{x ^{6}}

= - \frac{15}{x ^{6}}

\frac{\partial}{\partial v} (u sin (v))

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\int \frac{( 2 x + 4 )}{x ^{2} + 5 x - 6} d x

\int \frac{1}{t ^{2} - 6 t + 25} d t

\frac{d}{d x} (cos (ln (3 x)))

What is the derivative of 3x^{-5} ?
The derivative of 3x^{-5} is -(15)/(x^6)
What is the first derivative of 3x^{-5} ?
The first derivative of 3x^{-5} is -(15)/(x^6)