What is the integral from 2 to 7 of 1/(sqrt(x-2)) ?

The integral from 2 to 7 of 1/(sqrt(x-2)) is 2sqrt(5)

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integral from 2 to 7 of 1/(sqrt(x-2))

\int_{2}^{7} \frac{1}{x - 2} d x

25

Decimal Notation

4.47213 \dots

Solution steps

\int_{2}^{7} \frac{1}{x - 2} d x

Apply u-substitution

: \int_{0}^{5} 2 d u

= \int_{0}^{5} 2 d u

Integral of a constant:

\int a d x = a x

= [2 u]_{0}^{5}

Compute the boundaries:

25

= 25

f (x) = e^{4 x s i n (2 x)}

\frac{\partial}{\partial x} (\frac{e ^{x}}{u ( x ) + x ^{2}})

y^{^{''}} - \frac{9}{x} y^{^{'}} + \frac{34}{x ^{2}} y = 0

\frac{d y}{d x} = 5 y + 2

\frac{6 x + 2 x ^{2}}{( 3 + 2 x ) ^{2}}

What is the integral from 2 to 7 of 1/(sqrt(x-2)) ?
The integral from 2 to 7 of 1/(sqrt(x-2)) is 2sqrt(5)