What is (\partial)/(\partial v)(u^2+v^2) ?

The answer to (\partial)/(\partial v)(u^2+v^2) is 2v

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(\partial)/(\partial v)(u^2+v^2)

\frac{\partial}{\partial v} (u^{2} + v^{2})

2 v

Solution steps

\frac{\partial}{\partial v} (u^{2} + v^{2})

Treat

u

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial v} (u^{2}) + \frac{\partial}{\partial v} (v^{2})

\frac{\partial}{\partial v} (u^{2}) = 0

\frac{\partial}{\partial v} (v^{2}) = 2 v

= 0 + 2 v

Simplify

= 2 v

1 - e^{- 0.4 t}

\int \frac{1}{5 + 2 x} d x

(x^{2} + 1)^{(x + 1)}

\frac{d}{d x} (\frac{2 x + 5}{3})

f (x) = x arctan (x)

What is (\partial)/(\partial v)(u^2+v^2) ?
The answer to (\partial)/(\partial v)(u^2+v^2) is 2v