What is (\partial)/(\partial x)(zsin(x)+y^2) ?

The answer to (\partial)/(\partial x)(zsin(x)+y^2) is zcos(x)

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(\partial)/(\partial x)(zsin(x)+y^2)

\frac{\partial}{\partial x} (z sin (x) + y^{2})

z cos (x)

Solution steps

\frac{\partial}{\partial x} (z sin (x) + y^{2})

Treat

z, y

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (z sin (x)) + \frac{\partial}{\partial x} (y^{2})

\frac{\partial}{\partial x} (z sin (x)) = z cos (x)

\frac{\partial}{\partial x} (y^{2}) = 0

= z cos (x) + 0

Simplify

= z cos (x)

\int \frac{x}{( x + 2 ) ^{\frac{2}{3}}} d x

x \to 0 lim (cos (\frac{π}{2}))

y = 8 e^{x} cos (x)

\int \frac{( x + 1 )}{x} d x

\int \frac{1}{e ^{2 x} + 1} d x

What is (\partial)/(\partial x)(zsin(x)+y^2) ?
The answer to (\partial)/(\partial x)(zsin(x)+y^2) is zcos(x)