What is laplacetransform cos(ax+b) ?

The answer to laplacetransform cos(ax+b) is (scos(b)-asin(b))/(s^2+a^2)

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laplacetransform cos(ax+b)

laplace transform

cos (a x + b)

\frac{s cos ( b ) - a sin ( b )}{s ^{2} + a ^{2}}

Solution steps

L {cos (a x + b)}

Use Laplace Transform table:

L {cos (a t + b)} = \frac{s \cdot cos ( b ) - a \cdot sin ( b )}{s ^{2} + a ^{2}}

L {cos (a x + b)} = \frac{s cos ( b ) - a sin ( b )}{s ^{2} + a ^{2}}

= \frac{s cos ( b ) - a sin ( b )}{s ^{2} + a ^{2}}

\frac{d}{d x} (\frac{( x ^{2} )}{7 + 6 x})

\int 5 (1 - x)^{4} d x

\int \frac{24}{x ^{3}} d x

x \to 1 lim (\frac{x - 3}{x ^{2} + 4})

\frac{d y}{d x} = x + y, y (0) = 3

What is laplacetransform cos(ax+b) ?
The answer to laplacetransform cos(ax+b) is (scos(b)-asin(b))/(s^2+a^2)